In our discussion of the periodic table, we saw how trends in the ionization energies of a select group of elements suggested the existence of electron shells. Figure 1 expands the graph of ionization energies presented previously to include 26 of the first 36 elements. The data in the figure are color coded by row in the periodic table. The first row consists of hydrogen and helium. The second row contains lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon.The large decrease in ionization energy that occurs between helium and lithium defines the end of the first row and the beginning of the second. A similar pattern defines the other rows.
Exercise 2 The third row in Figure 1 starts at atomic number , ends at atomic number, and contains elements.
Exercise 3 The fourth row in Figure 1 starts at atomic number , ends at atomic number, and contains elements.
Exercise 5 What is the name of the element that has the electron configuration 1s22s22p3 ?
a. C b. N c. Ne d. Na+1
Figure 3 compares the first and second ionization energies of six elements, using the same color coding as Figure 1. In all cases the second ionization energy is greater than the first. This is because it is more difficult to separate an electron from a positively charged ion than it is from the corresponding neutral atom. The interesting feature of Figure 3 is that the second ionization energies of Be, Mg, and Ca are all much less than the second ionization energies of the elements that precede them, i.e. Li, Na, and K, respectively. Not surprisingly, this result may be rationalized in terms of electron configurations.
Exercise 8 Select the atom or ion that has a filled shell electron configuration.
a. Be Be+1 Be+2
b. Na Na+1 Na+2
c. Mg Mg+1 Mg+2
d. K K+1 K+2
e. Ca Ca+1 Ca+2
Exercise 9 Select the element that should have the lowest 3rd ionization energy.
Li Be B C
Topics